Oxidation numbers of
atoms
There is a clear
relationship between oxidation number (or oxidation state) atom and its
position in the periodic table. Oxidation number of atoms in covalent compounds
atoms is defined as an imaginary charge which will be owned when the electrons
are shared equally divided between bonded atoms (atoms that are bonded
together) or handed over all the atoms are more strongly appeal (if different
atoms bonded ).
(1) GROUP KEY
ELEMENTS
For the main group
elements, oxidation in many cases is the number of electrons will be released
or received to achieve the full electron configuration, ns2np6 (except for the
first period) or an electron configuration nd10.
It is clear for
elements of low period which is a member group 1, 2 and 13-18. For larger
periods, the trend has oxidation associated with the configuration of the
electrons with the electrons retained ns and np electrons are removed. For
example, lead tin Sn and Pb, both class 14, has a +2 oxidation state by
removing electrons NP2 but retain ns2 electrons, in addition to the oxidation
state +4. The same reasoning can be used to the fact that phosphorus P and
bismuth Bi, two groups of 15 with electron configuration ns2np3, has an
oxidation state of +3 and +5.
Generally, the
importance of ns2 electron oxidation to be maintained will become increasingly
important for a greater period. For nitrogen and phosphorus compounds,
oxidation number +5 dominant, while the dominant bismuth is +3 and +5 oxidation
state rather rare.
Metallic elements
and semilogam (Si silicon or germanium Ge) rarely has a negative oxidation
value, but for non-metals are common phenomena. In nitrogen and phosphorus
hydride, NH3 and PH3, oxidation of N and P are-3. The higher period elements,
the element will lose these properties and bismuth Bi does not have a negative
oxidation. Among the group 16 elements, oxidation-2 dominant as in the case of
oxygen O. This trend will again decline to elements in higher periods. Suppose
oxygen only has a negative oxidation number, but it's had such a positive
oxidation state +4 and +6 are also significant.
(2) ELEMENTS OF
TRANSITION
Although the
transition elements have multiple oxidation states, regularity can be
recognized. Highest oxidation number of atoms that have five electrons the
number of d orbitals associated with the current state of all the d electrons
(electrons than s) removed. So, in the case of scandium with electron
configuration (n-1) d1ns2, oxidation number 3. Manganese configuration with
(n-1) d5ns2, will berbilangan maximum oxidation +7.
If the amount
exceeds 5 d electrons, the situation changed. For iron Fe with electron
configuration (n-1) d6ns2, primarily oxidation +2 and +3. Very rare oxidation
state +6. Highest oxidation number a number of important transition metals such
as cobalt Co, Ni Nickel, copper and zinc Zn Cu lower oxidation states of atoms
lose all electrons (n-1) d and ns it. Among the elements that are in the same
group, the higher the oxidation state of the elements essential for a greater
period.
Concept of Oxidation
Numbers
Understanding
Oxidation Numbers:
Electric charge as
if possessed by the elements in a compound or ion.
OXIDATION NUMBERS
PRICE
1. Oxidation
Bialngan free element = 0
2. Oxygen
In compounds
Oxidation Numbers = -2
except
a. In peroxide,
Oxidation Numbers = -1
b. In superoxide,
Numbers Oxide = -1 / 2
c. In of2, Oxidation
Numbers = +2
3. Hydrogen
In compounds,
Oxidation Numbers = +1
Except in hybrid =
-1
4. The elements of
Group IA
In compounds,
Oxidation Numbers = +2
5. The elements of
Group IIA
In compounds,
Oxidation Numbers = +2
6. Oxidation Numbers
molecule = 0
7. Oxidation Numbers
ion = charge on the ion
8. Halogens
F: 0, -1
Cl: 0, -1, +1, +3,
+5, +7
Br: 0, -1, +1, +5,
+7
I: 0, -1, +1, +5, +7
In my article mentioned that to
BalasHapusIn the oxygen compounds, oxidation Numbers = -2
except
a. In peroxide, Oxidation Numbers = -1
b. In superoxide, Numbers Oxide = -1 / 2
c. In of2, Oxidation Numbers = +2
the problem is why the price is different oxidation numbers? whereas both oxygen, what distinguishes peroxide, superoxide, and so has the price of2 different oxygen oxidation
The determination of the oxidation state based on the difference in price
BalasHapuskeelektronegatifannya. Electropositive elements greater value and positive oxidation states
the more electronegative element negative oxidation state values.
The oxidation state of oxygen (O) -2 umumya misalya O in CO2 and H2O. Unless O = -1 in H2O2 and O = + 2 of2
Oxygen Elements when the peroxide compound; oxidation state of O = -1 but when the compound nonPeroksida; oxidation state of O = -2.
I'll try to answer your question, it is because oxygen includes elements have values that depend on the oxidation reaction occurred (exception) that include, among others peroxide, H2O2. This compound is a neutral compound, so the sum of the oxidation states of hydrogen and oxygen must be zero.
BalasHapusBecause each hydrogen has an oxidation state of +1, the oxidation state of each oxygen must be -1, hydrogen to balance it.
I'll try to answer of question yuor ask a friend
BalasHapusbecous end reaction in is the perenstion in it unit the end of ocsigent thet notmaces the sam number as the one your asket was the of ned
The determination of the oxidation state based on the difference in price
keelektronegatifannya. Electropositive elements greater value and positive oxidation states
the more electronegative element negative oxidation state values.
The oxidation state of oxygen (O) -2 umumya misalya O in CO2 and H2O.